There is only one empty cell left in row 7 so we can enter the 1 there. Entering the 1 in row 7 eliminates all other possibilities for the 1 in block 2 so we can enter a 1 in the lower left-hand cell.

Entering the 1 in row 3 eliminates one of the possibilities for the 7 in that block so we can enter the 7 and that in turn eliminates one of the two 7s in block 8 and allows us to enter the 7 there.

Checking column 4, we need to place the 4 and 9. There's already a 4 in row 2 so the 4 must go in row 5 and the 9 in row 2.

In row 5 we are missing the 3 and 9. The 3 has to go in block 4 (there is already a 9 there) and the 9 in block 5. This leaves one empty cell in each of these blocks. So enter the 3 and the 4 in their respective cells. Next page>

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